Physics Question from JEE Main 2023 · 8 April, Shift 1

For a nucleus $^{A}_{Z}X$ having mass number $A$ and atomic number $Z$:

A. The surface energy per nucleon $b_s = -a_1 A^{2/3}$.

B. The Coulomb contribution to the binding energy $b_c = -a_2 \dfrac{Z(Z-1)}{A^{4/3}}$.

C. The volume energy $b_v = a_3 A$.

D. Decrease in the binding energy is proportional to surface area.

E. While estimating the surface energy, it is assumed that each nucleon interacts with $12$ nucleons.

($a_1$, $a_2$ and $a_3$ are constants.)

Choose the most appropriate answer from the options given below: