MCQEasyJEE Main 2026 · 24 January, Shift 2Atomic Mass & Binding Energy

Physics Question from JEE Main 2026 · 24 January, Shift 2

The binding energy for the following nuclear reactions are expressed in MeV\text{MeV}.

23He+01n24He+20MeV{}^{3}_{2}He + {}^{1}_{0}n \rightarrow {}^{4}_{2}He + 20 \, \text{MeV} 24He+01n25He0.9MeV{}^{4}_{2}He + {}^{1}_{0}n \rightarrow {}^{5}_{2}He - 0.9 \, \text{MeV}

If X3,X4,X5X_3, X_4, X_5 denote the stability of 23He,24He{}^{3}_{2}He, {}^{4}_{2}He and 25He{}^{5}_{2}He, respectively, then the correct order is:

  • A

    X4>X5>X3X_4 > X_5 > X_3

  • B

    X4=X5=X3X_4 = X_5 = X_3

  • C

    X4>X5<X3X_4 > X_5 < X_3

  • D

    X4<X5<X3X_4 < X_5 < X_3

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