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MCQEasyJEE Main 2026 · 22 January, Shift 1Atomic Mass & Binding Energy

Physics Question from JEE Main 2026 · 22 January, Shift 1

The minimum frequency of photon required to break a particle of mass 15.34815.348 amu into 44 particles is _____ kHz.

[Mass of He nucleus =4.002=4.002 amu, 11 amu =1.66×10−27=1.66\times10^{-27} kg, h=6.6×10−34h=6.6\times10^{-34} J⋅\cdots and c=3×108c=3\times10^8 m/s]

  • A

    9×10199\times10^{19}

  • B

    9×10209\times10^{20}

  • C

    14.94×102014.94\times10^{20}

  • D

    14.94×101914.94\times10^{19}

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