MCQEasyJEE Main 2023 · 8 April, Shift 1Limits

Mathematics Question from JEE Main 2023 · 8 April, Shift 1

limx0((1cos2(3x))cos3(4x))(sin3(4x)(loge(2x+1))5)\lim_{x \to 0} \left( \frac{\left(1 - \cos^2(3x)\right)}{\cos^3(4x)} \right)\left( \frac{\sin^3(4x)}{\left(\log_e(2x + 1)\right)^5} \right) is equal to:

  • A

    2424

  • B

    99

  • C

    1818

  • D

    1515

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