JEE Physics 2023 Question with Solution

Given: initial velocity $u = 10.0 \, \text{m/s}$, final velocity $v = 60.0 \, \text{m/s}$, and uniform acceleration $a = 2.0 \, \text{m/s}^2$.

Find: the time $t$ taken to reach $60.0 \, \text{m/s}$.

Use the equation of motion:

$$v = u + at$$

Substitute the given values:

$$60 = 10 + 2t$$

So,

$$2t = 50$$

Hence,

$$t = 25 \, \text{s}$$

Therefore, the time taken is $25 \, \text{s}$. The correct option is C.

Given: $u = 10 \, \text{m/s}$, $v = 60 \, \text{m/s}$, $a = 2 \, \text{m/s}^2$.

Find: $t$.

Using the first equation of motion:

$$t = \frac{v-u}{a}$$

Substitute the values:

$$t = \frac{60-10}{2}$$ $$t = \frac{50}{2} = 25 \, \text{s}$$

Therefore, the time taken to attain a speed of $60 \, \text{m/s}$ is $25 \, \text{s}$, so the correct option is C.