JEE Physics 2023 Question with Solution

Given: A uniformly charged thin spherical shell.

Find: The graph of electric potential $V$ as a function of radial distance $r$ from the center.

For a thin spherical shell, the electric potential is constant everywhere inside the shell:

$$V = \frac{KQ}{R}$$

for $r \le R$.

Outside the shell, the potential is the same as that due to a point charge placed at the center:

$$V = \frac{KQ}{r}$$

for $r > R$.

So, from the center up to $r = R$, the graph is a horizontal line. Beyond $r = R$, the potential decreases with $r$ following an inverse relation.

Therefore, the correct option is D.