MCQEasyJEE 2023Group 14 Elements

JEE Chemistry 2023 Question with Solution

The correct order of bond enthalpy (kJ mol1\text{kJ mol}^{-1}) is:

  • A

    Si -- Si >> C -- C >> Sn -- Sn >> Ge -- Ge

  • B

    Si -- Si >> C -- C >> Ge -- Ge >> Sn -- Sn

  • C

    C -- C >> Si -- Si >> Sn -- Sn >> Ge -- Ge

  • D

    C -- C >> Si -- Si >> Ge -- Ge >> Sn -- Sn

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: We need the correct order of bond enthalpy for C -- C, Si -- Si, Ge -- Ge, and Sn -- Sn bonds.

Find: Which option matches the decreasing bond enthalpy order.

Bond enthalpy generally decreases down a group because atomic size increases and bond length becomes larger, making the bond weaker.

For Group 1414 elements, the atomic size order is:

C<Si<Ge<Sn\text{C} < \text{Si} < \text{Ge} < \text{Sn}

Therefore, bond enthalpy decreases in the reverse order:

C-C>Si-Si>Ge-Ge>Sn-Sn\text{C-C} > \text{Si-Si} > \text{Ge-Ge} > \text{Sn-Sn}

This corresponds to option D. However, the solution states The Correct Option is A, which disagrees with its own working. Using the solution working, the correct option is D.

Common mistakes

  • Assuming bond enthalpy increases down the group is incorrect because larger atoms form longer and weaker bonds. Use the trend of increasing atomic size to infer decreasing bond strength.

  • Following the listed option letter without checking the solution working is wrong here because the solution text contradicts the option label. Match the derived order with the actual options.

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