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MCQEasyJEE Main 2023 · 1 February, Shift 2Biot–Savart Law

Physics Question from JEE Main 2023 · 1 February, Shift 2

As shown in the figure, a long straight conductor with a semicircular arc of radius π10 m\frac{\pi}{10} \, \text{m} is carrying current I=3 AI = 3 \, \text{A}. The magnitude of the magnetic field at the center O of the arc is: (The permeability of the vacuum = 4π×10−7 N A−24\pi \times 10^{-7} \, \text{N A}^{-2})

A straight wire carries current 3 A into a semicircular arc above the line, then continues straight. Center O is marked with a radius arrow to the arc.
  • A

    6μT6\mu\text{T}

  • B

    1μT1\mu\text{T}

  • C

    4μT4\mu\text{T}

  • D

    3μT3\mu\text{T}

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