MCQMediumJEE Main 2023 · 1 February, Shift 2Sum of Series

Mathematics Question from JEE Main 2023 · 1 February, Shift 2

The sum n=12n2+3n+4(2n)!\sum_{n=1}^{\infty} \frac{2n^2 + 3n + 4}{(2n)!} is equal to:

  • A

    11e2+72e\frac{11e}{2} + \frac{7}{2e}

  • B

    13e4+54e4\frac{13e}{4} + \frac{5}{4e} - 4

  • C

    11e2+72e4\frac{11e}{2} + \frac{7}{2e} - 4

  • D

    13e4+54e\frac{13e}{4} + \frac{5}{4e}

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