NVAEasyJEE Main 2023 · 31 January, Shift 2Electrolytic Conductance & Kohlrausch's Law

Chemistry Question from JEE Main 2023 · 31 January, Shift 2

The resistivity of a 0.8M0.8 \, \text{M} solution of an electrolyte is 5×103Ωcm5 \times 10^{-3} \, \Omega \, \text{cm}. Its molar conductivity is _____ ×104Ω1cm2mol1\times \, 10^4 \, \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} (nearest integer).

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Electrolytic Conductance & Kohlrausch's Law questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions