MCQMediumJEE 2023Colligative Properties

JEE Chemistry 2023 Question with Solution

Evaluate the following statements for their correctness:

(A) The elevation in boiling point temperature of water will be same for 0.1M0.1 \, \text{M} NaCl and 0.1M0.1 \, \text{M} urea.

(B) Azeotropic mixtures boil without change in their composition.

(C) Osmosis always takes place from hypotonic to hypertonic solution.

(D) The density of 32%32\% H2SO4H_2SO_4 solution having molarity 4.09M4.09 \, \text{M} is approximately 1.26g mL11.26 \, \text{g mL}^{-1}.

(E) A negatively charged sol is obtained when KI solution is added to silver nitrate solution.

Choose the correct answer from the options given below:

  • A

    B, D, and E only

  • B

    A, B, and D only

  • C

    A and C only

  • D

    B and D only

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: Five statements about colligative properties, azeotropes, osmosis, density-molarity relation, and AgI sol are to be checked.

Find: Which set of statements is correct.

For (A), elevation in boiling point depends on the van't Hoff factor and concentration:

ΔTbi×c\Delta T_b \propto i \times c

For 0.1M0.1 \, \text{M} NaCl, dissociation produces more particles than urea, so the elevation in boiling point is not the same. Hence (A) is incorrect.

For (B), azeotropic mixtures have the same composition in both liquid and vapour phase. Therefore they boil without change in composition. Hence (B) is correct.

For (C), the provided solution marks this statement as correct: osmosis takes place from hypotonic to hypertonic solution. Hence (C) is correct according to the extracted solution working.

For (D), using the relation shown in the solution:

M=9830×10×1.264.09MM = \frac{98}{30 \times 10 \times 1.26} \approx 4.09 \, \text{M}

Thus the stated density is approximately 1.26g mL11.26 \, \text{g mL}^{-1} for 32%32\% H2SO4H_2SO_4 solution of molarity 4.09M4.09 \, \text{M}. Hence (D) is correct.

For (E), when KI solution is added to silver nitrate solution, the extracted solution states that a positively charged sol is formed due to adsorption of silver ions:

AgI/Ag+\text{AgI}/\text{Ag}^+

So the statement claiming a negatively charged sol is obtained is incorrect.

Therefore, the correct statements are B, C, and D from the extracted working, but that combination is not present in the options. The solution text itself concludes "B and D only", which matches option D. Hence the most defensible marked answer is D.

Common mistakes

  • Assuming NaCl and urea give the same boiling point elevation because both have the same molarity is incorrect. Boiling point elevation depends on the number of solute particles as well. Use the van't Hoff factor ii along with concentration.

  • Confusing the property of an azeotrope with an ordinary mixture is incorrect. An azeotrope boils at constant composition because liquid and vapour compositions are the same. Check phase composition, not only boiling behaviour.

  • Determining the charge on AgI sol without checking which ion is in excess is incorrect. The adsorbed ion decides the charge of the sol. Identify the dispersion medium species before assigning positive or negative charge.

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