MCQMediumJEE Main 2023 · 31 January, Shift 1Limits

Mathematics Question from JEE Main 2023 · 31 January, Shift 1

The number of real roots of the equation x24x+3+x29=4x214x+6\sqrt{x^2 - 4x + 3} + \sqrt{x^2 - 9} = \sqrt{4x^2 - 14x + 6} is:

  • A

    00

  • B

    11

  • C

    33

  • D

    22

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Limits questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions