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MCQEasyJEE 2023VSEPR Theory & Shapes of Molecules

JEE Chemistry 2023 Question with Solution

Match List I with List II

List I List II A. XeF4XeF_4 I. See-saw B. SF4SF_4 II. Square planar C. NH4+NH_4^+ III. Bent T-shaped D. BrF3BrF_3 IV. Tetrahedral

Choose the correct answer from the options given below:

  • A

    A-IV, B-III, C-II, D-I

  • B

    A-II, B-III, C-III, D-IV

  • C

    A-I, B-I, C-II, D-III

  • D

    A-I, B-I, C-IV, D-III

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: Molecules XeF4XeF_4, SF4SF_4, NH4+NH_4^+ and BrF3BrF_3 are to be matched with their molecular shapes.

Find: The correct matching and hence the correct option.

Use VSEPR theory to identify the shape of each species from the number of bonding pairs and lone pairs.

  • XeF4XeF_4 has square planar geometry.
  • SF4SF_4 has see-saw shape.
  • NH4+NH_4^+ has tetrahedral geometry.
  • BrF3BrF_3 has bent T-shaped structure.

Therefore, the correct matching is A-II, B-I, C-IV, D-III.

This corresponds to option C as concluded in the solution, even though the raw option text for option C shows a mismatch. The defensible answer from the solution is C.

Diagram showing shapes of XeF4 square planar, SF4 see-saw, NH4 plus tetrahedral, and BrF3 bent T-shaped with lone pairs marked.

Shape-wise Matching

Given: A matching question based on molecular geometry.

Find: Which list pairing is correct.

From the extracted solution:

  1. A. XeF4XeF_4 has a square planar structure.
  2. B. SF4SF_4 has a see-saw shape.
  3. C. NH4+NH_4^+ has a tetrahedral geometry.
  4. D. BrF3BrF_3 has a bent T-shaped structure.

So the matching becomes:

  • A →\to II
  • B →\to I
  • C →\to IV
  • D →\to III

Hence, the correct matching is A-II, B-I, C-IV, D-III.

Therefore, the correct option is C.

Common mistakes

  • Confusing electron pair geometry with molecular shape. For example, XeF4XeF_4 has octahedral electron pair arrangement but its molecular shape is square planar because lone pairs are not counted as bonded atoms in the final shape.

  • Assuming SF4SF_4 is tetrahedral because it has four fluorine atoms. This is incorrect because one lone pair is also present on sulfur, giving a trigonal bipyramidal electron arrangement and a see-saw molecular shape.

  • Treating BrF3BrF_3 as trigonal planar or simple T-shaped without considering lone pairs properly. Two lone pairs on bromine distort the arrangement, so the structure is identified here as bent T-shaped in the provided solution.

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