Let be the set of all values of for which the mean deviation about the mean of consecutive positive integers is . Then is:
- A
- B
- C
- D
Let be the set of all values of for which the mean deviation about the mean of consecutive positive integers is . Then is:
Correct answer:C
Standard Method
Given: The numbers are consecutive positive integers starting from , so they are .
Find: The set of all values of for which the mean deviation about the mean is .
The solution states that can be any natural number.
First compute the mean:
Now the mean deviation about the mean is
For these equally spaced consecutive integers, the deviations from the mean are symmetric, so the expression becomes
The sum of the first odd numbers is
Hence
This value is independent of . Therefore, the condition is satisfied for every natural number . The correct option is C.
Translation Invariance Trick
Given: The numbers are consecutive integers shifted by .
Find: Whether the mean deviation depends on .
Adding the same constant to every observation shifts the mean by the same amount, but leaves all deviations from the mean unchanged. Therefore, the mean deviation about the mean for
is the same as that for
For consecutive integers, the data are symmetric about the mean, and the mean deviation evaluates to . Hence it is true for every natural number , so . The correct option is C.
Assuming the mean deviation depends on . This is wrong because shifting every term by the same constant shifts the mean equally and does not change the absolute deviations. Instead, focus on the spacing of the numbers, not their starting point.
Using the mean as or . This is wrong because the mean of consecutive integers from to is the average of the first and last terms, namely . Always use midpoint of the first and last term.
Summing the deviations incorrectly by ignoring symmetry. This is wrong because the deviations occur in equal pairs on both sides of the mean. Instead, write one side of the deviations and double it.
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