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MCQMediumJEE Main 2023 · 30 January, Shift 2Biot–Savart Law

Physics Question from JEE Main 2023 · 30 January, Shift 2

As shown in the figure, a current of 2 A2 \, \text{A} flowing in an equilateral triangle of side 43 cm4\sqrt{3} \, \text{cm}. The magnetic field at the centroid OO of the triangle is:

Equilateral triangle carrying current 2 A along all three sides, with centroid O marked inside and current directions shown on each side.
  • A

    43×10−4 T4\sqrt{3} \times 10^{-4} \, \text{T}

  • B

    43×10−5 T4\sqrt{3} \times 10^{-5} \, \text{T}

  • C

    3×10−4 T\sqrt{3} \times 10^{-4} \, \text{T}

  • D

    33×10−5 T3\sqrt{3} \times 10^{-5} \, \text{T}

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