JEE Chemistry 2023 Question with Solution

Step-by-step solution

Standard Method

Given: The alkene shown reacts with cold $\mathrm{H_2SO_4}$ to form A and with $\mathrm{H_2SO_4}$ at $80^\circ\text{C}$ to form B.

Find: The major products A and B respectively.

In the given reaction, electrophilic substitution of the phenyl group with a sulfate group is induced. The major products are:

Therefore, the correct option is B.

Common mistakes

• Assuming the answer key key is always correct. Here the provided answer key says (1), but the solution explicitly concludes option B. The solution working is the primary source, so use the solution conclusion.

• Reversing the products A and B. The conditions are different: cold $\mathrm{H_2SO_4}$ and $80^\circ\text{C}$ do not give the same major product order. Match each product carefully with its corresponding condition.

• Ignoring the role of reaction conditions in alkene reactions. Temperature and acid conditions affect whether addition or further rearranged product formation becomes major. Always connect the product to the specific condition written over the arrow.