MCQMediumJEE Main 2023 · 30 January, Shift 1Sum of Series

Mathematics Question from JEE Main 2023 · 30 January, Shift 1

If an=24n216n+15a_n = \frac{-2}{4n^2 - 16n + 15}, then a1+a2++a25a_1 + a_2 + \dots + a_{25} is equal to:

  • A

    51144\frac{51}{144}

  • B

    49138\frac{49}{138}

  • C

    50141\frac{50}{141}

  • D

    52147\frac{52}{147}

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