Given: Initial coil has n=4 turns and magnetic induction at the center is B=32T. The wire is rewound into a single-turn circular coil with the same current.
Find: The new magnetic induction B′ at the center.
For a circular coil of n turns,
B=2Rμ0ni
Initially,
B=2Rμ0i×4
When the four-turn coil is unwound and rewound into a single turn, the total length of wire remains the same. Hence the circumference of the new coil becomes 4 times the original circumference, so the new radius is
R′=4R
For the new single-turn coil,
B′=2R′μ0i
Substituting R′=4R,
B′=8Rμ0i
Now compare with the initial field:
BB′=4μ0i/(2R)μ0i/(8R)=161
Therefore,
B′=16B=1632=2T
So, the magnetic induction at the center becomes 2T. Therefore, the correct option is C.
The solution marks B, but its own working gives 2T, which matches option C.