NVAMediumJEE Main 2023 · 29 January, Shift 2Geometric Progression (GP)

Mathematics Question from JEE Main 2023 · 29 January, Shift 2

Let {ak}\{a_k\} and {bk}\{b_k\}, kNk \in \mathbb{N}, be two G.P.s with common ratios r1r_1 and r2r_2 respectively, such that a1=b1=4a_1 = b_1 = 4 and r1<r2r_1 < r_2. Let ck=ak+bkc_k = a_k + b_k, kNk \in \mathbb{N}. If c2=5c_2 = 5 and c3=134c_3 = \frac{13}{4}, then k=1ck(12a6+8b4)\sum_{k=1}^{\infty} c_k - (12a_6 + 8b_4) is equal to:

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