MCQMediumJEE Main 2025 · 7 April, Shift 1Geometric Progression (GP)

Mathematics Question from JEE Main 2025 · 7 April, Shift 1

Let x1,x2,x3,x4x_1, x_2, x_3, x_4 be in a geometric progression. If 22, 77, 99, 55 are subtracted respectively from x1,x2,x3,x4x_1, x_2, x_3, x_4, then the resulting numbers are in an arithmetic progression. Then the value of 124(x1x2x3x4)\frac{1}{24}(x_1 x_2 x_3 x_4) is:

  • A

    7272

  • B

    1818

  • C

    3636

  • D

    216216

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