Jeeify
MCQMediumJEE Main 2026 · 21 January, Shift 2Geometric Progression (GP)

Mathematics Question from JEE Main 2026 · 21 January, Shift 2

Let a1,a22,a322,…,a1029a_1, \frac{a_2}{2}, \frac{a_3}{2^2}, \dots, \frac{a_{10}}{2^9} be a G.P. of common ratio 12\frac{1}{\sqrt{2}}. If a1+a2+⋯+a10=62a_1 + a_2 + \dots + a_{10} = 62, then a1a_1 is equal to :

  • A

    2−22 - \sqrt{2}

  • B

    2(2−2)2(2 - \sqrt{2})

  • C

    2−1\sqrt{2} - 1

  • D

    2(2−1)2(\sqrt{2} - 1)

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Sign in to see the solution

Practice more Geometric Progression (GP) questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trialMore on Geometric Progression (GP)

Related questions