MCQMediumJEE Main 2023 · 29 January, Shift 2Sum of Series

Mathematics Question from JEE Main 2023 · 29 January, Shift 2

Consider a function f:NRf : \mathbb{N} \to \mathbb{R} satisfying f(1)+2f(2)+3f(3)++xf(x)=x(x+1)f(x)f(1) + 2f(2) + 3f(3) + \dots + x f(x) = x(x + 1) f(x) for x2x \geq 2, with f(1)=1f(1) = 1. Then 1f(2022)+1f(2028)\dfrac{1}{f(2022)} + \dfrac{1}{f(2028)} is equal to:

  • A

    82008200

  • B

    80008000

  • C

    84008400

  • D

    81008100

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