NVAEasyJEE Main 2023 · 29 January, Shift 1Gibbs Free Energy & Equilibrium Constant

Chemistry Question from JEE Main 2023 · 29 January, Shift 1

Consider the following reaction approaching equilibrium at 27∘C27^\circ \text{C} and 1 atm1 \, \text{atm} pressure:

A+B⇌C+DA + B \rightleftharpoons C + D

Kf=103K_f = 10^3, Kr=102K_r = 10^2

The standard Gibbs energy change (ΔrG∘\Delta_r G^\circ) at 27∘C27^\circ \text{C} is (−)(-) _____ kJ mol−1\text{kJ mol}^{-1} (Nearest integer).

(Given: R=8.3 J K−1 mol−1R = 8.3 \, \text{J K}^{-1} \, \text{mol}^{-1} and ln⁡(10)=2.3\ln(10) = 2.3)

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