JEE Chemistry 2023 Question with Solution

Given: A matching question between named reactions in List-I and reagents in List-II.

Find: The correct option that matches each reaction with its reagent.

From the extracted solution:

• Hoffmann Degradation Reaction uses $Br_2$ and $NaOH$ to convert amides into amines. Therefore, reagent is (III).
• Clemmensen Reduction reduces ketones or aldehydes to alkanes using $Zn-Hg$ in $HCl$. Therefore, reagent is (IV).
• Cannizzaro Reaction involves aldehydes without $\alpha$-hydrogen in concentrated alkali. Therefore, reagent is (I).
• Reimer-Tiemann Reaction introduces a $-CHO$ group into phenols using $CHCl_3$ and $NaOH$. Therefore, reagent is (II).

So the final matching is:

$$(A) \to III, \quad (B) \to IV, \quad (C) \to I, \quad (D) \to II$$

This corresponds to Option C.

The solution states "The Correct Option is B", but its own working gives the mapping of Option C. Using the solution working, the defensible answer is C.