MCQMediumJEE Main 2023 · 29 January, Shift 1Self & Mutual Inductance

Physics Question from JEE Main 2023 · 29 January, Shift 1

Find the mutual inductance in the arrangement, when a small circular loop of radius RR is placed inside a large square loop of side LL (LRL \gg R). The loops are coplanar and their centers coincide:

  • A

    M=2μ0R2/LM = \sqrt{2}\mu_0R^2 / L

  • B

    M=22μ0R/L2M = 2\sqrt{2}\mu_0R / L^2

  • C

    M=22μ0R2/LM = 2\sqrt{2}\mu_0R^2 / L

  • D

    M=2μ0R/L2M = \sqrt{2}\mu_0R / L^2

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Self & Mutual Inductance questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions