Consider I₁ and I₂ are the currents flowing simultaneously in two nearby coils 1 & 2, respectively. If L₁ = se…

Question

Consider $$I_1$$ and $$I_2$$ are the currents flowing simultaneously in two nearby coils $$1$$ & $$2$$, respectively. If $$L_1$$ = self inductance of coil $$1$$, $$M_{12}$$ = mutual inductance of coil $$1$$ with respect to coil $$2$$, then the value of induced emf in coil $$1$$ will be:

Accepted Answer

C. $$e_1 = -L_1 \frac{dI_1}{dt} - M_{12} \frac{dI_2}{dt}$$

Answer

A. $$e_1 = -L_1 \frac{dI_2}{dt} + M_{12} \frac{dI_1}{dt}$$

Answer

B. $$e_1 = -L_1 \frac{dI_1}{dt} + M_{12} \frac{dI_2}{dt}$$

Answer

D. $$e_1 = -L_1 \frac{dI_1}{dt} + M_{12} \frac{dI_1}{dt}$$

Answer & step-by-step solution

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