MCQEasyJEE 2023Biot–Savart Law

JEE Physics 2023 Question with Solution

The magnitude of magnetic induction at the mid-point OO due to the current arrangement shown in the figure is:

  • A

    μ0I/(2πa)\mu_0 I / (2\pi a)

  • B

    00

  • C

    μ0I/(4πa)\mu_0 I / (4\pi a)

  • D

    μ0I/(πa)\mu_0 I / (\pi a)

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: The magnetic field at the mid-point OO is to be found for the given current arrangement.

Find: The magnitude of magnetic induction at OO.

Magnetic field contributions due to segments BCBC and ETET are outward at point OO.

Total magnetic field:

B=μ0I4πr+μ0I4πr=μ0IπaB = \frac{\mu_0 I}{4 \pi r} + \frac{\mu_0 I}{4 \pi r} = \frac{\mu_0 I}{\pi a}

Therefore, the correct option is D and the magnitude of magnetic induction is μ0Iπa\frac{\mu_0 I}{\pi a}.

Answer Discrepancy Note

The solution states "The Correct Option is C", but the worked expression concludes

B=μ0IπaB = \frac{\mu_0 I}{\pi a}

which matches option D in the listed options. Hence the worked result is used as the final answer.

Common mistakes

  • Adding the fields with the wrong direction. Here both contributions are outward at OO, so they add; they should not be subtracted.

  • Matching the final expression to the mislabeled option letter in the solution instead of the actual option values. Always compare the derived field expression with the listed options.

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