MCQMediumJEE 2023Biot–Savart Law

JEE Physics 2023 Question with Solution

A single current-carrying loop of wire carrying current II flows in the anticlockwise direction (seen from the +z+z direction) and lies in the xyxy plane. The plot of the j^\hat{j} component of magnetic field (ByB_y) at a distance aa (less than the radius of the coil) and on the yzyz plane vs zz coordinate looks like:

  • A

    (Not shown)

  • B

    (Not shown)

  • C

    (Correct graph)

  • D

    (Not shown)

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: A circular current loop lies in the xyxy plane and carries current II in the anticlockwise direction when seen from the +z+z direction. We need the variation of ByB_y on the yzyz plane at a fixed distance aa from the center, with aa less than the loop radius.

Find: The correct graph of ByB_y versus zz.

Using symmetry of the circular loop and the right-hand rule:

By=0atz=0B_y = 0 \quad \text{at} \quad z=0

At the plane of the loop, the j^\hat{j} component cancels by symmetry. Also, the direction of ByB_y reverses when zz changes from positive to negative.

By(+z)=By(z)B_y(+z) = -B_y(-z)

So, ByB_y is an odd function of zz. Therefore the required graph must pass through the origin and have opposite signs on the two sides of z=0z=0.

The solution explicitly states that the correct option is A. This disagrees with the answer key, which marks option (3). Since the solution is the primary source, the answer is taken as A.

Therefore, the correct option is A.

Common mistakes

  • Assuming the magnetic field is entirely along the zz-axis everywhere is incorrect. Away from the axis, the field can have transverse components such as ByB_y. Use symmetry at the specified point, not only the on-axis result.

  • Taking ByB_y to have the same sign for +z+z and z-z is incorrect. The right-hand rule shows that the j^\hat{j} component reverses sign across the plane of the coil, so treat ByB_y as an odd function of zz.

  • Concluding that ByB_y is nonzero at z=0z=0 is incorrect. In the plane of the loop, symmetry makes the yy-components cancel at the specified location. Check component-wise cancellation before sketching the graph.

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