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MCQMediumJEE Main 2023 · 25 January, Shift 1Limits

Mathematics Question from JEE Main 2023 · 25 January, Shift 1

The value of lim⁡n→∞1+2−3+4+5−6+…+(3n−2)+(3n−1)−3n2n4+4n+3−n4+5n+4\lim_{n \to \infty} \frac{1 + 2 - 3 + 4 + 5 - 6 + \ldots + (3n - 2) + (3n - 1) - 3n}{\sqrt{2n^4 + 4n + 3} - \sqrt{n^4 + 5n + 4}} is:

  • A

    2+12\frac{\sqrt{2} + 1}{2}

  • B

    3(2+1)3(\sqrt{2} + 1)

  • C

    32(2+1)\frac{3}{2}(\sqrt{2} + 1)

  • D

    322\frac{3}{2\sqrt{2}}

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