NVAMediumJEE Main 2023 · 24 January, Shift 2Sum of Series

Mathematics Question from JEE Main 2023 · 24 January, Shift 2

If 13+23+33+(up to n terms)13+25+37+(up to n terms)=95\frac{1^3 + 2^3 + 3^3 + \ldots (\text{up to } n \text{ terms})}{1 \cdot 3 + 2 \cdot 5 + 3 \cdot 7 + \ldots (\text{up to } n \text{ terms})} = \frac{9}{5}, then the value of nn is:

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