MCQMediumJEE Main 2026 · 28 January, Shift 2Significant Figures & Error Analysis

Physics Question from JEE Main 2026 · 28 January, Shift 2

The time period of a simple harmonic oscillator is T=2πmk.T=2\pi\sqrt{\frac{m}{k}}. Measured value of mass mm of the object is 10g10\,\text{g} with an accuracy of 10mg10\,\text{mg} and time for 5050 oscillations of the spring is found to be 60s60\,\text{s} using a watch of 2s2\,\text{s} resolution. Percentage error in determination of spring constant kk is:

  • A

    7.60%7.60\%

  • B

    6.76%6.76\%

  • C

    3.43%3.43\%

  • D

    3.35%3.35\%

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Significant Figures & Error Analysis questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions