MCQEasyJEE Main 2026 · 21 January, Shift 1Significant Figures & Error Analysis

Physics Question from JEE Main 2026 · 21 January, Shift 1

In an experiment the values of two spring constants were measured as k1=(10±0.2)N/mk_1 = (10 \pm 0.2)\, \text{N/m} and k2=(20±0.3)N/mk_2 = (20 \pm 0.3)\, \text{N/m}. If these springs are connected in parallel, then the percentage error in equivalent spring constant is:

  • A

    1.33%1.33\%

  • B

    1.67%1.67\%

  • C

    2.33%2.33\%

  • D

    2.67%2.67\%

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