NVAMediumJEE Main 2026 · 28 January, Shift 1Refraction & Lenses

Physics Question from JEE Main 2026 · 28 January, Shift 1

A convex lens of refractive index 1.51.5 and focal length f=18cmf=18 \, \text{cm} is immersed in water. The difference in focal lengths of the given lens when it is in water and in air is α×f\alpha \times f. Find the value of α\alpha. (Given: refractive index of water =43=\dfrac{4}{3})

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