MCQMediumJEE Main 2026 · 28 January, Shift 1Equation of Line in 3D

Mathematics Question from JEE Main 2026 · 28 January, Shift 1

If the distances of the point (1,2,a)(1,2,a) from the line x11=y2=z11\frac{x-1}{1}=\frac{y}{2}=\frac{z-1}{1} along the lines L1: x13=y24=zabL_1:\ \frac{x-1}{3}=\frac{y-2}{4}=\frac{z-a}{b} and L2: x11=y24=zacL_2:\ \frac{x-1}{1}=\frac{y-2}{4}=\frac{z-a}{c} are equal, then a+b+ca+b+c is equal to:

  • A

    55

  • B

    66

  • C

    44

  • D

    77

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