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MCQMediumJEE Main 2026 · 23 January, Shift 1Equation of Line in 3D

Mathematics Question from JEE Main 2026 · 23 January, Shift 1

The vertices B and C of a triangle ABC lie on the line x1=1−y−2=z−23\frac{x}{1} = \frac{1-y}{-2} = \frac{z-2}{3}. The coordinates of A and B are (1,6,3)\left(1, 6, 3\right) and (4,9,α)\left(4, 9, \alpha\right) respectively and C is at a distance of 1010 units from B. The area (in sq. units) of △ABC\triangle ABC is:

  • A

    101310\sqrt{13}

  • B

    151315\sqrt{13}

  • C

    5135\sqrt{13}

  • D

    201320\sqrt{13}

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