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MCQEasyJEE 2026Valency & Oxidation States

JEE Chemistry 2026 Question with Solution

**X**'' is an oxoanion of the lightest element of group **$$17$$** (in the periodic table). The metal is in **$$+6$$** oxidation state in X''. The color of the potassium salt of X is

  • A

    purple

  • B

    green

  • C

    orange

  • D

    yellow

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: X is an oxoanion of the lightest element of group 1717 and the element in X is in +6+6 oxidation state.

Find: The color of the potassium salt of X.

The solution identifies the lightest element of group 1717 as chlorine.

For chlorine oxoanions, the species stated in the solution is chlorate ion, ClO3−\text{ClO}_3^-.

Its potassium salt is potassium chlorate, KClO3\text{KClO}_3.

The provided solution concludes that potassium chlorate appears greenish in crystalline form under standard conditions.

Therefore, the correct option is B (green).

Common mistakes

  • Confusing the lightest group 1717 element with fluorine and then searching for a fluorine oxoanion. Fluorine does not commonly form analogous positive oxidation state oxoanions here. First identify the intended halogen from the solution's context.

  • Matching the oxidation state incorrectly. Students may associate chlorine oxoanions loosely without checking the oxidation number. Always calculate the oxidation state before selecting the species.

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