MCQEasyJEE 2024Valency & Oxidation States

JEE Chemistry 2024 Question with Solution

Element not showing variable oxidation state is:

  • A

    Bromine

  • B

    Iodine

  • C

    Chlorine

  • D

    Fluorine

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: The options are Bromine, Iodine, Chlorine, and Fluorine.

Find: The element that does not show variable oxidation state.

Halogens generally show different oxidation states, but Fluorine is an exception.

  • Fluorine is the most electronegative element.
  • Therefore, it shows only oxidation state 1-1.
  • It does not show positive oxidation states.
  • Chlorine, Bromine, and Iodine can show multiple oxidation states such as 1,+1,+3,+5,+7-1, +1, +3, +5, +7.

Therefore, the element not showing variable oxidation state is Fluorine. The correct option is D.

Note: The solution incorrectly labels the option as B, but the worked conclusion identifies Fluorine, which corresponds to option D in the given options.

Key Exception Trick

Given: A halogen is to be identified which does not show variable oxidation state.

Find: The correct option.

Remember the standard exception: Fluorine is the most electronegative element, so it practically always has oxidation state 1-1 only.

Thus, among the given halogens, Fluorine alone does not show variable oxidation states. The correct option is D.

Common mistakes

  • Assuming all halogens show variable oxidation states is incorrect because Fluorine is an exception. Its very high electronegativity restricts it to oxidation state 1-1 only. Always check for standard exceptions in periodic trends.

  • Following the option label written in the solution without matching it to the actual option text is wrong. Here the solution says option B, but the worked conclusion gives Fluorine, which is option D in the provided list. Always verify the option text.

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