MCQEasyJEE 2026Electronic Effects (Inductive, Resonance, Hyperconjugation)

JEE Chemistry 2026 Question with Solution

Given below are two statements: Statement I: (CH3)3C+\left( CH_3 \right)_3C^+ is more stable than CH3CH2+CH_3CH_2^+ as nine hyperconjugation interactions are possible in (CH3)3C+\left( CH_3 \right)_3C^+. Statement II: CH3+CH_3^+ is less stable than (CH3)3C+\left( CH_3 \right)_3C^+ as only three hyperconjugation interactions are possible in CH3+CH_3^+. In the light of the above statements, choose the correct answer...

  • A

    Statement I is false but Statement II is true

  • B

    Both Statement I and Statement II are false

  • C

    Both Statement I and Statement II are true

  • D

    Statement I is true but Statement II is false

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: Two statements compare the stability of carbocations using hyperconjugation.

Find: Which statement is true.

Hyperconjugation depends on the number of α\alpha-hydrogens attached to the carbon adjacent to the positively charged carbon.

For Statement I:

(CH3)3C+\left( CH_3 \right)_3C^+

has 99 α\alpha-hydrogens, while

CH3CH2+CH_3CH_2^+

has 33 α\alpha-hydrogens. Therefore, tert-butyl cation is more stable than ethyl cation due to greater hyperconjugation. So, Statement I is true.

For Statement II:

CH3+CH_3^+

has 00 α\alpha-hydrogens, so 00 hyperconjugative structures are possible, not 33. Therefore, Statement II is false.

Hence, the correct option is D.

Common mistakes

  • Counting hydrogens of the positively charged carbon as α\alpha-hydrogens. This is wrong because hyperconjugation requires C-H bonds on the carbon adjacent to the positively charged carbon. Always count hydrogens on the adjacent carbon only.

  • Assuming CH3+CH_3^+ has three hyperconjugation interactions because it contains three hydrogens. This is incorrect because there is no adjacent carbon in methyl cation. Therefore, there are 00 α\alpha-hydrogens and no hyperconjugation.

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