In Carius method 0.2425 g of an organic compound gave 0.5253 g silver chloride. The percentage of chlorine in the organic compound is

Given: Mass of organic compound = 0.2425 g, mass of AgCl obtained = 0.5253 g. Find: Percentage of chlorine in the organic compound. In Carius estimation, Cl = Atomic mass of Cl Molar mass of AgCl Mass of AgCl Mass of compound 100 Molar mass of AgCl is 108 + 35.5 = 143.5 g/mol Substituting the given values, Cl = 35.5143.5 0.52530.2425 100 Cl = 0.24738 2.1662 100 53.58 Therefore, the percentage of chlorine is 53.58. The correct option is C.

In Carius method 0.2425 g of an organic compound gave 0.5253 g si… — Solution | JEE Chemistry

MCQEasyJEE 2026Quantitative Analysis (C, H, N…)

In Carius method $0.2425 \, \text{g}$ of an organic compound gave $0.5253 \, \text{g}$ silver chloride. The percentage of chlorine in the organic compound is

A
$37.57\%$
B
$34.79\%$
C
$53.58\%$
D
$87.65\%$

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: Mass of organic compound = $0.2425 \, \text{g}$ , mass of AgCl obtained = $0.5253 \, \text{g}$ .

Find: Percentage of chlorine in the organic compound.

In Carius estimation,

\% \text{Cl} = \frac{\text{Atomic mass of Cl}}{\text{Molar mass of AgCl}} \times \frac{\text{Mass of AgCl}}{\text{Mass of compound}} \times 100

Molar mass of AgCl is

108 + 35.5 = 143.5 \, \text{g/mol}

Substituting the given values,

\% \text{Cl} = \frac{35.5}{143.5} \times \frac{0.5253}{0.2425} \times 100

\% \text{Cl} = 0.24738 \times 2.1662 \times 100 \approx 53.58\%

Therefore, the percentage of chlorine is $53.58\%$ . The correct option is C.

Common mistakes

Using the mass of AgCl directly as the mass of chlorine is incorrect because only the chlorine part of AgCl contributes to chlorine percentage. Always multiply by the ratio $\frac{35.5}{143.5}$ first.
Taking the molar mass of AgCl incorrectly causes a wrong answer. Use $108 + 35.5 = 143.5 \, \text{g/mol}$ , not only the atomic mass of silver or chlorine alone.
Dividing by the wrong sample mass is a common error. The denominator must be the mass of the original organic compound, $0.2425 \, \text{g}$ , not the mass of AgCl.

Practice more Quantitative Analysis (C, H, N…) questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step — free to start.

Start free trial More on Quantitative Analysis (C, H, N…)

Answer

Step-by-step solution

Common mistakes

Practice more Quantitative Analysis (C, H, N…) questions

Related questions