JEE Chemistry 2026 Question with Solution

Given: $0.53 \, \text{g}$ of compound $X$ gives $0.75 \, \text{g}$ of $\text{AgBr}$, and $1.0 \, \text{g}$ of $X$ gives $1.32 \, \text{g}$ of $\text{CO}_2$ on combustion.

Find: Percentage of hydrogen in compound $X$.

From the solution, the displayed correct answer is $4$. The working shown on the page computes bromine and carbon masses, but then reaches $32\%$ hydrogen, which contradicts the displayed correct answer. Hence, the solution contains an internal discrepancy.

Using the shown working:

So, moles of bromine $\approx 0.004$ and mass of bromine is

Also,

Thus mass of carbon is

The shown page then takes mass of hydrogen as

and obtains

However, this does not match the displayed final answer on the solution's.

Therefore, following the solution's authority for answer extraction, the final extracted answer is $4$.

Given: the solution lists Correct Answer: $4$.

Find: The answer to be recorded from the provided source.

The numerical working present in the working is inconsistent with that listed answer. Since the extraction rule gives priority to the source solution conclusion when available, the answer is recorded as $4$.

Therefore, the numerical value answer is $4$.