MCQMediumJEE Main 2026 · 23 January, Shift 2Complex Numbers Basics

Mathematics Question from JEE Main 2026 · 23 January, Shift 2

If z=32+i2z = \frac{\sqrt{3}}{2} + \frac{i}{2}, then (z201i)8(z^{201} - i)^8 is equal to

  • A

    00

  • B

    256256

  • C

    1-1

  • D

    11

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