MCQMediumJEE Main 2026 · 21 January, Shift 1Complex Numbers Basics

Mathematics Question from JEE Main 2026 · 21 January, Shift 1

If x2+x+1=0x^2+x+1=0, then the value of (x+1x)4+(x2+1x2)4+(x3+1x3)4++(x25+1x25)4\left(x + \frac{1}{x}\right)^4 + \left(x^2 + \frac{1}{x^2}\right)^4 + \left(x^3 + \frac{1}{x^3}\right)^4 + \dots + \left(x^{25} + \frac{1}{x^{25}}\right)^4 is:

  • A

    128128

  • B

    175175

  • C

    145145

  • D

    162162

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