Consider the following reduction processes: Al³⁺ + 3e⁻ → Al(s), E^° = -1.66 V Fe³⁺ + e⁻ → Fe²⁺, E^° = +0.77 V…

Question

Consider the following reduction processes:
$$ Al^{3+} + 3e^- \longrightarrow Al(s), \quad E^\circ = -1.66\,V $$
$$ Fe^{3+} + e^- \longrightarrow Fe^{2+}, \quad E^\circ = +0.77\,V $$
$$ Co^{3+} + e^- \longrightarrow Co^{2+}, \quad E^\circ = +1.81\,V $$
$$ Cr^{3+} + 3e^- \longrightarrow Cr(s), \quad E^\circ = -0.74\,V $$
The tendency to act as reducing agent decreases in the order:

Accepted Answer

C. $$Al > Cr > Fe^{2+} > Co^{2+}$$

Answer

A. $$Cr > Fe^{2+} > Al > Co^{2+}$$

Answer

B. $$Al > Cr > Co^{2+} > Fe^{2+}$$

Answer

D. $$Al > Fe^{2+} > Cr > Co^{2+}$$

Answer & step-by-step solution

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