MCQMediumJEE Main 2026 · 22 January, Shift 1Equation of State of Ideal Gas

Physics Question from JEE Main 2026 · 22 January, Shift 1

A cylindrical tube ABAB of length ll, closed at both ends, contains an ideal gas of 11 mol having molecular weight MM. The tube is rotated in a horizontal plane with constant angular velocity ω\omega about an axis perpendicular to ABAB and passing through the edge at end AA, as shown in the figure. If PAP_A and PBP_B are the pressures at AA and BB respectively, then (consider the temperature to be same at all points in the tube)

A horizontal cylindrical tube AB of length l is shown rotating about a vertical axis through end A with angular velocity omega, with gas inside and end B at the far right.
  • A

    PB=PAexp ⁣(Mω2l2RT)P_B = P_A \exp\!\left(\dfrac{M\omega^2l^2}{RT}\right)

  • B

    PB=PAP_B = P_A

  • C

    PB=PAexp ⁣(Mω2l23RT)P_B = P_A \exp\!\left(\dfrac{M\omega^2l^2}{3RT}\right)

  • D

    PB=PAexp ⁣(Mω2l22RT)P_B = P_A \exp\!\left(\dfrac{M\omega^2l^2}{2RT}\right)

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