Physics Question from JEE Main 2026 · 22 January, Shift 1

Net gravitational force at the center of a square is found to be $F_1$ when four particles having masses $M, 2M, 3M$ and $4M$ are placed at the four corners of the square as shown in figure, and it is $F_2$ when the positions of $3M$ and $4M$ are interchanged. The ratio $\dfrac{F_1}{F_2} = \dfrac{\alpha}{\sqrt{5}}$. The value of $\alpha$ is