MCQMediumJEE Main 2025 · 22 January, Shift 1Newton's Law of Gravitation

Physics Question from JEE Main 2025 · 22 January, Shift 1

A small point of mass mm is placed at a distance 2R2R from the center OO of a big uniform solid sphere of mass MM and radius RR. The gravitational force on mm due to MM is F1F_1. A spherical part of radius R/3R/3 is removed from the big sphere as shown in the figure, and the gravitational force on mm due to the remaining part of MM is found to be F2F_2. The value of the ratio F1:F2F_1 : F_2 is:

A large sphere with center O, a smaller spherical cavity of radius R by 3 removed along the radius toward an external point mass m placed at distance 2R from O.
  • A

    16:916 : 9

  • B

    11:1011 : 10

  • C

    12:1112 : 11

  • D

    12:912 : 9

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