MCQEasyJEE Main 2025 · 8 April, Shift 2Wave Motion Basics

Physics Question from JEE Main 2025 · 8 April, Shift 2

Two strings with circular cross section and made of same material are stretched to have same amount of tension. A transverse wave is then made to pass through the strings. The velocity of the wave in the first string having the radius of cross section RR is v1v_1, and that in the other string having radius of cross section R/2R/2 is v2v_2. Then, v2v1\frac{v_2}{v_1} is:

  • A

    44

  • B

    2\sqrt{2}

  • C

    88

  • D

    22

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