NVAEasyJEE Main 2025 · 7 April, Shift 2Electric Field & Field Lines

Physics Question from JEE Main 2025 · 7 April, Shift 2

The electric field in a region is given by E=(2i^+4j^+6k^)×103N/C\vec{E} = (2\hat{i} + 4\hat{j} + 6\hat{k}) \times 10^3 \, \text{N/C}. The flux of the field through a rectangular surface parallel to x-z plane is 6.0N m2C16.0 \, \text{N m}^2\text{C}^{-1}. The area of the surface is _____ cm2\text{cm}^2.

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Electric Field & Field Lines questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions