MCQEasyJEE Main 2025 · 22 January, Shift 1Electric Field & Field Lines

Physics Question from JEE Main 2025 · 22 January, Shift 1

An electron is made to enters symmetrically between two parallel and equally but oppositely charged metal plates, each of 10cm10 \, \text{cm} length. The electron emerges out of the field region with a horizontal component of velocity 106m/s10^6 \, \text{m/s}. If the magnitude of the electric field between the plates is 9.1V/cm9.1 \, \text{V/cm}, then the vertical component of velocity of electron is (mass of electron = 9.1×1031kg9.1 \times 10^{-31} \, \text{kg} and charge of electron = 1.6×1019C1.6 \times 10^{-19} \, \text{C}):

  • A

    1×106m/s1 \times 10^6 \, \text{m/s}

  • B

    00

  • C

    16×106m/s16 \times 10^6 \, \text{m/s}

  • D

    16×104m/s16 \times 10^4 \, \text{m/s}

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