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MCQMediumJEE Main 2025 · 7 April, Shift 2Equation of Line in 3D

Mathematics Question from JEE Main 2025 · 7 April, Shift 2

If the equation of the line passing through the point (0,−12,0)\left( 0, -\frac{1}{2}, 0 \right) and perpendicular to the lines r1=λ(i^+aj^+bk^)andr2=(i^−j^−6k^)+μ(−bi^+aj^+5k^)\mathbf{r_1} = \lambda ( \hat{i} + a \hat{j} + b \hat{k}) \quad \text{and} \quad \mathbf{r_2} = ( \hat{i} - \hat{j} - 6 \hat{k} ) + \mu( -b \hat{i} + a \hat{j} + 5 \hat{k}), is x−1−2=y+4d=z−c−4\frac{x - 1}{-2} = \frac{y + 4}{d} = \frac{z - c}{-4}, then a+b+c+da + b + c + d is equal to:

  • A

    1010

  • B

    1414

  • C

    1313

  • D

    1212

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